5.6w^2=7w+18

Solution for 5.6w^2=7w+18 equation:

5.6w^2=7w+18

We move all terms to the left:

5.6w^2-(7w+18)=0

We get rid of parentheses

5.6w^2-7w-18=0

a = 5.6; b = -7; c = -18;
Δ = b2-4ac
Δ = -72-4·5.6·(-18)
Δ = 452.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{452.2}}{2*5.6}=\frac{7-\sqrt{452.2}}{11.2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{452.2}}{2*5.6}=\frac{7+\sqrt{452.2}}{11.2}
$